The length of a rectangle is 1 cm more than two times its breadth.its perimeter is 80 cm. what is its length?
Answers
Answered by
7
Let the breadth be x
Let the length be 1 + 2x
Perimeter = 80
So 80 = 2(x + 1 + 2x)
= 2(3x +1)
80 = 6x + 2
80 - 2 = 6x
78/6 = x
13 = x
Length = 27
Breadth = 13
Let the length be 1 + 2x
Perimeter = 80
So 80 = 2(x + 1 + 2x)
= 2(3x +1)
80 = 6x + 2
80 - 2 = 6x
78/6 = x
13 = x
Length = 27
Breadth = 13
anuabhi68:
thank you
Answered by
4
Let's assume the breadth as x cm
So, the length as (2x + 1) cm
We know,
Perimeter of Rectangle
= 2(length + breadth)
According to Question,
Perimeter of Rectangle = 80 cm
2(2x + 1 + x) = 80
⇒ 3x + 1 = 80 / 2
⇒ 3x + 1 = 40
⇒ 3x = 40 - 1
⇒ 3x = 39
⇒ x = 39 / 3
⇒ x = 13
Required Measurements -
Breadth = x = 13 cm
Length = 2x + 1 = 2(13) + 1 = 26 + 1 = 27 cm
Hence, the length and breadth of the rectangle are 27 cm and 13 cm respectively
✪ Be Brainly ✪
So, the length as (2x + 1) cm
We know,
Perimeter of Rectangle
= 2(length + breadth)
According to Question,
Perimeter of Rectangle = 80 cm
2(2x + 1 + x) = 80
⇒ 3x + 1 = 80 / 2
⇒ 3x + 1 = 40
⇒ 3x = 40 - 1
⇒ 3x = 39
⇒ x = 39 / 3
⇒ x = 13
Required Measurements -
Breadth = x = 13 cm
Length = 2x + 1 = 2(13) + 1 = 26 + 1 = 27 cm
Hence, the length and breadth of the rectangle are 27 cm and 13 cm respectively
✪ Be Brainly ✪
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