Question

The length of a rectangle is 10/3 cm more than its breadth. If its breadth is equal to the side of a square whose perimeter is 24 cm, then the area of rectangle in square cm will be

Answer 1

Answer:

let breadth of rectangle be xcm

it's length=10/3+x cm

a to q

side of square=breadth of rectangle==x cm

perimeter of square=24cm

4 *side=24

4x=24

x=6cm

breadth of rectangle=6cm

length of rectangle=10/3+6

=28/3cm

area of rectangle=length*breadth

area of rectangle=28/3*6

area of rectangle=56cm square

Answer 2

Answer:

The length of a rectangle is 10/3 cm more than its breadth. If its breadth is equal to the side of a square whose perimeter is 24 cm, then the area of rectangle in square cm will be

Let length of rectangle=lcm

breadth of rectangle= bcm

Given length is 3 times its breadth

i.e. l= 3×b

Perimeter of the rectangle= 120 cm

i.e.2×( l+ b)=120

 2×(3×b+ b)=120

 2×(4×b)=120

 8×b=120

 b= 15 cm