Question

The length of a rectangle is 10 cm and it's perimeter is equal to that of a square of side 9 .find the area of rectangle​

Answer 1

Answer

${80cm}^{2}$

Given .

The length of a rectangle is 10 cm.and a square of side 9 cm.

Find

Area of the Rectangle ?

Solution

Perimeter of square = 4 × side .

4 × 9cm

36cm.

Now According to questions

Perimeter of rectangle = perimeter of square.

here the length of rectangle is 10 cm .and breadth is b.

2 ( l + b ) = 4 × Side

2( 10 + b ) = 4 × 9cm

20 + 2b = 36cm

2b = 36 - 20

2b = 16 cm

$\begin{gathered}b \: = \frac{16}{2} \\ \\ = 8\end{gathered}$

Again here we find Area of rectangle.

Area of rectangle = length × breadth.

10 cm × 8cm.

${80cm}^{2}80cm$

Therefore the area of rectangle is equal to

${80cm}^{2}$

Be brainly