Question

the length of a rectangle is 10 cm and its perimeter is equal to the square of side 9 cm find the area of the rectangle​

Answer 1

Answer:

• Given

Length of rectangle =10cm

Side of square=9cm

Perimeter of square= 4×a=4×9=36cm

According to the given question

Perimeter of square= perimeter of rectangle

2(l+b)=36

l+b = 36/2

l+b=18

b=18 -l {put the value of length of rectangle}

b=18 - 10

b = 8

Aera of rectangle =l ×b

=10×8=80cm²

Step-by-step explanation:

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Answer 2

Solution:-

Perimeter of rectangle=2(l+b)

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ=2(10+b)

Perimeter of square=4×l

ㅤㅤㅤㅤㅤㅤㅤㅤㅤ=4×9

ㅤㅤㅤㅤㅤㅤㅤㅤㅤ=36 cm

• In question it is given that length of rectangle=perimeter of square..

⇢20+2b=36 cm

Moving 20 to RHS

⇢2b=36-20

⇢2b=16

⇢b=$\sf \dfrac{16}{2}$

⇢b=8 cm

________________

Area of rectangle=L×B

ㅤㅤㅤㅤㅤㅤㅤㅤ=10×8

ㅤㅤ$\sf \pink{⇢80 \ cm^2}$