Question

the length of a rectangle is 10 cm and its perimeter is equal to that of a square of side 9 cm. find the area of the rectangle.

Answer 1

Perimeter of rectangle = 2(L+B) = 2(10+x)

Perimeter of square = 4xs = 4x9 = 36 cm

Given 2(10+x) = 36

20+2x=36

x=(36-20)/2 = 8

Area of rectangle = LxB = 10 x 8 = 80 cm squared

Answer 2

Answer

${80cm}^{2}$



Given .


The length of a rectangle is 10 cm.and a square of side 9 cm.


Find

Area of the Rectangle ?

Solution

Perimeter of square = 4 × side .

4 × 9cm

36cm.


Now According to questions


Perimeter of rectangle = perimeter of square.


here the length of rectangle is 10 cm .and breadth is b.


2 ( l + b ) = 4 × Side

2( 10 + b ) = 4 × 9cm

20 + 2b = 36cm

2b = 36 - 20

2b = 16 cm


$b \: = \frac{16}{2} \\ \\ = 8$
Again here we find Area of rectangle.

Area of rectangle = length × breadth.


10 cm × 8cm.


${80cm}^{2}$


Therefore the area of rectangle is equal to
${80cm}^{2}$


Be brainly