The length of a rectangle is 10 cm and the breadth is y. If the rectangle is an equable shape, then the value of y?
Answers
Given:
The length of a rectangle is 10 cm and the breadth is y. The rectangle is an equable shape.
To find out:
Find the value of y?
Formula used:
- Perimeter of rectangle = 2 ( l + b )
- Area of rectangle = length × Breadth
Solution:
Let the length be x and breadth be y.
⋆ length = x = 10 cm [ Given ]
According to question:-
Perimeter of rectangle = Area of rectangle
→ 2 ( x + y ) = x × y
→ 2 ( 10 + y ) = 10 × y
→ 20 + 2y = 10 y
→ 10y - 2y = 20
→ 8y = 20
→ y = 20/8
→ 2.5 cm
Hence, the value of y is 2.5 cm
Given:
The length of the rectangle is 10cm and the breadth is 1 .the rectangle is an equable shape.
To find out:
Find the value of y?
Formula used:
perimeter of rectangle = 2(l + b)
area of rectangle = length × breadth
Solutions:
let the length be x and breadth by y.
length = x = 10cm
A.Q.T
perimeter of rectangle = area of rectangle
2(l + b) = x × y
2(10 + y) = 10 × y
20 + 2y = 10y
20 = 10y - 2y
20 = 8y
y = 2.5cm
Hence, the value of y is 2.5cm.
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