Question

The length of a rectangle is 10 cm more than its breadth. if the breadth is 30cm.what will be the area of the rectangle.​

Answer 1

Let the length be 30+10
40=length
30=breath
(30+10+30)2=perimeter
(70)2=140cm
Area
(40)(30)=120cm^2

Answer 2

$\huge{ \underline{ \overline{ \mid{ \mathfrak{ \purple{ \: \: ANSWER \: \: } \mid}}}}}$

$\underline{ \mathfrak{ \: \: Given, \: \: }} \\ \\ \: \: \: \: \text{Breadth = 30 cm} \\ \\ \text{Length is 10 cm more than breadth} \\ \\ \therefore \: \: \text{Length = (30 + 10) cm = 40 cm}$

$\underline{ \mathfrak{ \: \: We \: \: know \: \: that, \: \: }} \\ \\ \boxed{ \bold{ \: \:Area \: \: of \: \: a \: \: rectangle = Length \times Breadth \: \: }}</p><p>$

$\tt{ \therefore \: \: Area \: \: of \: \: the \: \: rectangle } \\ \\ \: \: \: \: \: \: \: \: \: \: \: \tt{= Length \times Breadth } \\ \\ \: \: \: \: \: \: \: \: \: \: \: \tt{= (40 \times 30) \: \: cm {}^{2} } \\ \\ \: \: \: \: \: \: \: \: \: \: \: \tt{= 1200 \: \: cm {}^{2} }$