The length of a rectangle is 10 m more than its breadth if the perimeter of rectangle is 80m find the dimensions of the rectangle
Answers
ATQ, the Length of the rectangle is 10m more than it's breadth.
let the breadth of the rectangle be x
therefore it's length = x + 10
given perimeter of the rectangle = 80m
formula to find the perimeter of a rectangle = 2 ( l + b )
➡ 2 ( l + b ) = 80m
➡ 2 ( x + 10 + x ) = 80m
➡ 2x + 10 = 80/2
➡ 2x = 40 - 10
➡ 2x = 30
➡ x = 30/2
➡ x = 15m
hence,
- breadth of the rectangle = x = 15m
- length of the rectangle = x + 10 = 25m
verification :-
= 2 ( l + b )
= 2(25 + 15)
= 2 × 40
= 80m
Answer:
Step-by-step explanation:
Given :-
Length of a rectangle is 10 m more than its breadth if the perimeter of rectangle is 80 m.
To Find :-
Dimensions of the rectangle.
Formula to be used :-
Perimeter of Rectangle = 2(length + breadth)
Solution :-
Let the breadth be = x
Then the length = x + 10
Putting all the values, we get
⇒ 2(length + breadth) = Perimeter of Rectangle
⇒ 2(x + 10 + x ) = 80
⇒ 2( 2x + 10) = 80
⇒ 4x +20 = 80
⇒ 4x = 80 - 20
⇒ 4x = 60
⇒ x = 60/4
⇒ x = 15
Breadth = 15 m
Length = 15 + 10 = 25 m
Hence, the dimensions of the rectangle are 15 m and 25 m.