Math, asked by sabashia3446, 11 months ago

The length of a rectangle is 10 m more than its breadth if the perimeter of rectangle is 80m find the dimensions of the rectangle

Answers

Answered by Anonymous
37

ATQ, the Length of the rectangle is 10m more than it's breadth.

let the breadth of the rectangle be x

therefore it's length = x + 10

given perimeter of the rectangle = 80m

formula to find the perimeter of a rectangle = 2 ( l + b )

➡ 2 ( l + b ) = 80m

➡ 2 ( x + 10 + x ) = 80m

➡ 2x + 10 = 80/2

➡ 2x = 40 - 10

➡ 2x = 30

➡ x = 30/2

➡ x = 15m

hence,

  • breadth of the rectangle = x = 15m

  • length of the rectangle = x + 10 = 25m

verification :-

= 2 ( l + b )

= 2(25 + 15)

= 2 × 40

= 80m

Answered by VishalSharma01
111

Answer:

Step-by-step explanation:

Given :-

Length of a rectangle is 10 m more than its breadth if the perimeter of rectangle is 80 m.

To Find :-

Dimensions of the rectangle.

Formula to be used :-

Perimeter of Rectangle = 2(length + breadth)

Solution :-

Let the breadth be = x

Then the length = x + 10

Putting all the values, we get

2(length + breadth) = Perimeter of Rectangle

⇒ 2(x + 10 + x ) = 80

⇒ 2( 2x + 10) = 80

⇒ 4x +20 = 80

⇒ 4x = 80 - 20

⇒ 4x = 60

⇒ x = 60/4

x = 15

Breadth = 15 m

Length = 15 + 10 = 25 m

Hence, the dimensions of the rectangle are 15 m and 25 m.

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