Question

the length of a rectangle is 10 m more than its breadth.if the perimeter of rectangle is 80 m, find the area of the rectangle ​

Answer 1

Step-by-step explanation:

Let The breadth be 'x' cm

Therefore,The lenght ='x+10'cm

Perimeter Of the Rectangle=2(l+b)

80m=2(x+x+10)

=2(2x+10)

80 =4x+20

4x=80-20

x=60/4

x=15

Length=x=15m

Breadth=x+10=25m

Area of rectangle=l*b

=15*25

=375m2

Answer 2

$\huge{\underline{\sf{Question :-}}}}$

The length of a rectangle is 10 m more than its breadth. If the perimeter of rectangle is 80 m, find the area of the rectangle.

$\huge{\underline{\sf{Answer :-}}}}$

✯ Given,

➩ Perimeter = 80m

➩ 2 (l + b) = 80m

➩ l + b = 40

Now,

Let the breadth of the rectangle be

= x m.

Let the length of the rectangle be

= (x + 10) m.

Then,

➩ (x + 10) + x = 40

➩ 2x + 10 = 40

➩ 2x = 40 - 10

➩ 2x = 30

➩x = 15 m

Therefore,

➜ Breadth of the rectangle = x = 15 m

➜ Length of the rectangle = (x + 10) cm = 15 + 10 = 25 m

➜ Area of the rectangle = l × b = 25 × 15 = 375 m².

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