Question

The length of a rectangle is 10 m more than its breadth if the perimeter of rectangle is 80m find the dimensions of the rectangle.

Answer 1

Step-by-step explanation:

breadth=x

length=x+10

perimeter= 80m

2(l+b)=80

2(x+x+10)=80

2(2x+10)=80

4x+20=80

4x=80-20

4x=60

x=60/4

x=15

length=x+10

=15+10

=25m

breadth=15 m

Answer 2

Given :-

• Length of a rectangle is 10 m more tan its breadth.

• Perimeter of rectangle = 80 m.

To Find :-

• Dimensions of the rectangle.

Solution :-

Let the length and breadth of the rectangle be l & b.

Therefore,

Length = b + 10...(1)

Perimeter of the rectangle :-

$:\implies\sf{Perimeter = 2(l+b)}$

$:\implies\sf{80 = 2(l+b)}$

$:\implies\sf{80 = 2(l+10+b)}$

$:\implies\sf{2b+10=\dfrac{80}{2} }$

$:\implies\sf{2b+10=40}$

$:\implies\sf{2b=40-10}$

$:\implies\sf{2b=30}$

$:\implies\sf{b=\dfrac{30}{2}}$

$\sf:\implies \underline{\boxed{\pink{\mathfrak{b = 15}}}}$

So,

• Breadth of the rectangle = b = 15 m.

• Length of the rectangle = l = 15 + 10 = 25 m.

To check ↓

Perimeter of the rectangle :-

$:\implies\sf{2(l+b)}$

$:\implies\sf{2(15+25)}$

$:\implies\sf{2\times40}$

$:\implies\sf{80}$

Hence Verified!