Question

. The length of a rectangle is 10 m more than its bredth. if the perimeter of rectangle is 80 m . find the demensions of rectangle​

Answer 1

Given:-

• The length of a rectangle is 10 m more than its bredth.

• The Perimeter of Rectangle is 80m

To Find:-

• The Dimensions of Rectangle

Formulae used:-

• Perimeter of Rectangle = 2(L + B)

Where,

• L = Length

• B = Breadth.

Now,

Let the Breadth be "x"

→ Length of Rectangle ° x + 10

→ Perimeter of Rectangle = 2 ( x + x + 10)

→ 80 = 2 ( 2x + 10 )

→ 80/2 = 2x + 10

→ 40 = 2x + 10

→ 2x = 30

→ x = 15.

Hence, The Value of x is 15

Therefore,

→ Length = x + 10 → 15 + 10 = 25

→ Breadth = x = 15.

MORE FORMULAE:-

• Area of Rectangle = L × B

• Area of Square = 4 × Side

• Area of Rhombus = Product of Diagonal/2.

• Area of Parallelogram = Base × Height.

Answer 2

Step-by-step explanation:

let the length be (10+x) and breadth be x m.

The perimeter of a rectangle = 80m

The perimeter of a rectangle = 2(l+b)

80m = 2 (10+x+x)m

80m/2 = 2x + 10

40m - 10 = 2x

30m/2 = x

15m = x

length = (10+x)m = (10+15)m = 25m

Breadth = x m = 15 m