The length of a rectangle is 10 meters more than twice its width. What is the length and width of the rectangle if its perimeter is 62 meters
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Answer:
width=7 m
length=7*2+10=24 m
Step-by-step explanation:
perimeter =2(l+b)=62 m
let the width be x
so, it's length=2x+10
so, 2(x+2x+10)=62 m
(3x+10)=62/2
3x =31-10
x=21/3=7
hope u got your answer
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