Question

The length of a rectangle is 10 meters more than twice its width. What is the length and width of the rectangle if its perimeter is 62 meters. *

Answer 1

Answer:

Let the width of the rectangle be x metres.

So, width = x

ATQ,

Length = 2x + 10

MARK AS BRAINLIEST

Perimeter = 62 m

Perimeter of rectangle = 2(l + b)

62 = 2(2x + 10 + x)

62 = 2(3x + 10)

62 = 6x + 20

6x = 62 - 20

x = 42/6

x = 7 m = Width

So, length = 2 × 7 + 10 = 24 m