The length of a rectangle is 10 metres more than Its breadth l.if the perimeter of the rectangle is 80metres find the dimensions of the rectangle
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Answered by
6
Let the breadth be x
Then length is x+10
Given, perimeter is 80m
Perimeter=2×(l+b)
80=2×(x+10+x)
80/2= 2x+10
40-10 = 2x
30 = 2x
x = 15
Therefore..breadth is 15m
Length is x+10 = 15 + 10 =25.
Answered by
5
length (l) = b + 10
perimeter of rectangle = 2(l+b) = 80 m
2(b+10 +b) = 80 m
4b + 20 = 80 m
4b = 60 m
b = 60/4 = 15 m
l = b + 10 = 15 + 10 = 25 m
perimeter of rectangle = 2(l+b) = 80 m
2(b+10 +b) = 80 m
4b + 20 = 80 m
4b = 60 m
b = 60/4 = 15 m
l = b + 10 = 15 + 10 = 25 m
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