the length of a rectangle is 10meter more than its width. if the perimeter is 120meters. find its dimension
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Answered by
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Let the width of the Rect be x m.
Therefore, Length of Rect = x + 10 m.
Now,
Perimeter of Rectangle = 2(l + b)
=> 120 = 2(x + 10 + x)
=> 2x + 10 = 60
=> 2x = 50
=> x = 25 m.
Hence, length of Rect = 25 + 10
=> length of rectangle = 35 m.
And Breadth of Rectangle = 25 m.
Hope it helps u........
Therefore, Length of Rect = x + 10 m.
Now,
Perimeter of Rectangle = 2(l + b)
=> 120 = 2(x + 10 + x)
=> 2x + 10 = 60
=> 2x = 50
=> x = 25 m.
Hence, length of Rect = 25 + 10
=> length of rectangle = 35 m.
And Breadth of Rectangle = 25 m.
Hope it helps u........
Answered by
3
Heya ☺
Given that
Perimeter of a rectangle = 10 m
Length = ?
Breadth = ?
Solution
Let the breadth of a rectangle be (x) cm. Then,
it's length = (x + 10) cm
Perimeter of a rectangle = 2(l + b)
120 = 2(x + 10 + x)
=> 120 = 2(2x + 10)
=> 120 = 4x + 20
=> 120 - 20 = 4x
=> 100 = 4x
=> x = 100/4
=> x = 25
Hence , breadth = 25 cm
and length = (25 + 10) cm = 35 cm.
So , the dimensions of the rectangle is 25 cm and 35 cm.
Thanks
Given that
Perimeter of a rectangle = 10 m
Length = ?
Breadth = ?
Solution
Let the breadth of a rectangle be (x) cm. Then,
it's length = (x + 10) cm
Perimeter of a rectangle = 2(l + b)
120 = 2(x + 10 + x)
=> 120 = 2(2x + 10)
=> 120 = 4x + 20
=> 120 - 20 = 4x
=> 100 = 4x
=> x = 100/4
=> x = 25
Hence , breadth = 25 cm
and length = (25 + 10) cm = 35 cm.
So , the dimensions of the rectangle is 25 cm and 35 cm.
Thanks
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