Question

The length of a rectangle is 11 more than twice the breadth. The perimeter of the rectangle is 100. Then, find the length and breadth of the rectangle

Answer 1

S O L U T I O N :

Let the breadth of a rectangle be x unit & let the length of a rectangle be (2x+11) unit respectively.

The perimeter of the rectangle = 100 unit.

As we know that formula of the perimeter of rectangle;

$\boxed{\bf{Perimeter = 2(length + breadth)}}$

A/q

$\longrightarrow\tt{Perimeter\:of\:rectangle = 2(length + breadth)}$

$\longrightarrow\tt{100 = 2[(2x+11) + x]}$

$\longrightarrow\tt{100 = 2[2x+11+ x]}$

$\longrightarrow\tt{100 = 2[3x+11]}$

$\longrightarrow\tt{100 = 6x+22}$

$\longrightarrow\tt{ 6x = 100-22}$

$\longrightarrow\tt{ 6x = 78}$

$\longrightarrow\tt{ x = \cancel{78/6}}$

$\longrightarrow\bf{ x= 13\:unit}$

Thus,

The breadth of a rectangle = x = 13 unit .

The length of a rectangle = (2x+11) unit = [2(13) + 11] = [26 + 11] = 37 unit.