Question

The length of a rectangle is 12 cm more than it's breadth. if the perimeter is 48 cm. what are it's length and breadth

Answer 1

Answer:

l=12+b ----(1)

p= 48cm---(2)

we know p = 2(l+b) from (20

2(l+b)= 48

l+b= 24

12+b+b=24 from (1)

2b=12

b=6 thus L= 12+6=18

the length and breadth is 6cm and 18cm respectively

NOTE: l,b&p are length, breadth and perimeter respectively

Answer 2

Given :

• The length of a rectangle is 12 cm more than it's breadth.
• The perimeter is 48 cm.

To find :

• Length and breadth of the rectangle.

Solution :

Consider ,

• Length of rectangle = x cm
• Breadth of rectangle = y cm.

According to the 1st condition :-

• The length of a rectangle is 12 cm more than it's breadth.

$\implies\sf{x=y+12...................(i)}$

According to the 2nd condition :-

• The perimeter is 48 cm.

$\implies\sf{2(x+y)=48................(ii)}$

Now take the eq(ii).

$\implies\sf{2(x+y)=48}$

$\implies\sf{x+y=24}$

• Put x = y+12 from eq(1).

$\implies\sf{y+12+y=24}$

$\implies\sf{2y+12=24}$

$\implies\sf{2y=24-12}$

$\implies\sf{2y=12}$

$\implies\sf{y=6}$

• Breadth = 6 cm.

Now put y = 6 in eq (i) for getting the value of x.

$\implies\sf{x=y+12}$

$\implies\sf{x=6+12}$

$\implies\sf{x=18}$

• Length= 18 cm

Therefore, length is 18 cm and breadth is 6 cm.