Question

The length of a rectangle is 12 cmand it's diagonal is 13 cm.find it's area​

Answer 1

Answer:

Step-by-step explanation:

using pythagoras theorem (13)^2 = 12^2 +x^2 where x is the other side

x=5

therefore area = lb

12 (5) =60

Answer 2

$\huge \boxed{ \underline{ \underline{ \bf{Answer}}}}$

GIVEN :

Length = 12 cm

Diagonal = 13 cm

TO FIND :

Area of the rectangle.

Let's find the breadth of the rectangle.

In rt. ∆BCD ,

$\implies \: \sf {{BD}^{2} = \: {CD}^{2} + \: {BC}^{2}}$

$\implies \: \sf {{13}^{2} = \: {CD}^{2} \: + \: {12}^{2} }$

$\implies \: \sf{169 \: = \: {CD}^{2} + 144}$

$\implies \: \sf {{CD}^{2} = 169 - 144}$

$\implies \: \sf{ { CD }^{2} = \: 25}$

$\sf{ \implies \: CD (breadth)\: = \: 5 \: cm}$

Now, area of the rectangle = length × breadth.

= 12 × 5

= 60 cm^2.

${\boxed{ \sf{ Hence, \: Area \: of \: the \: rectangle = 60 {cm}^{2} }}}$