Question

The length of a rectangle is 12m more than twice the width. The area of the rectangle is 320 square m. Write an equation that can be used to find the length and width of the rectangle. Also find the dimensions of the rectangle.

Answer 1

let length of rectangle is x and width is y
according to question
x=2y+12
now area of rectangle=length x width
320 =x.y
put x=2y+12
320=(2y+12)(y)
=> y^2+6y-160=0
solve this by using question formula
i.e y={-6+_root (36+640)}/2= 10, -16
but y=-16 is not possible
hence y=10
and x=2y+12=32

Answer 2

ASSUME THAT W=X,L=2(W)+12
     AREA=320   BUT AREA =2(L+W)
  2(X+2*X+12)=320
2X+4X+24=320
6X+24=320
6X=320-24
6X=296
X=296/6=49.33333
Expression: 24+4w
Dimensions: l=160 w=74
DIMENSIONS ARE 160 AND 74 AS X AND Y
PLZ MARK IT AS BRAINLIEST