The length of a rectangle is 132 cm and its perimeter is equal to the perimeter of a square with side 100 cm . Find the area of the rectangle.
Answers
Answered by
16
Length=132 cm
Perimeter of square = Perimeter of rectangle
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4×S=2(l+b)
4×100=2(132+b)
400=2(132+b)
200=132+b
200-132=b
68cm=b
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Area of rectangle= l × b
=>132cm×68cm= >8976cm²
Perimeter of square = Perimeter of rectangle
===
===
4×S=2(l+b)
4×100=2(132+b)
400=2(132+b)
200=132+b
200-132=b
68cm=b
===
===
Area of rectangle= l × b
=>132cm×68cm= >8976cm²
Answered by
8
Perimeter of square = 100 x 4 = 400 cm
Now, Perimeter of rectangle = 2 x (L +B)
2 x (132 + B) = 400
264 + 2B = 400
2B = 400-264
2B = 136
and , B = 68 cm
now area = L x B
132 x 68
= 8976 cm²
Now, Perimeter of rectangle = 2 x (L +B)
2 x (132 + B) = 400
264 + 2B = 400
2B = 400-264
2B = 136
and , B = 68 cm
now area = L x B
132 x 68
= 8976 cm²
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