Math, asked by pamudeol, 1 month ago

The length of a rectangle is 15 cm greater than its breath. Its perimeter is 150cm. Find the dimension of the rectangle​

Answers

Answered by MяMαgıcıαη
141

Answer :

\:

  • Dimensions of a rectangle are 30 cm and 45 cm.

\:

⠀⠀⠀━━━━━━━━━━━━━━━━━━━━━━

\:

Explanation :

\:

Given :

\:

  • Length of a rectangle is 15 cm greater than its breadth.

  • It's perimeter is 150 cm.

\:

To Find :

\:

  • Dimensions of rectangle?

\:

Solution :

\:

  • Here, we are given that length of a rectangle is 15 cm greater than its breadth. So, Let's say that breadth be n cm. So, length is (n + 15) cm.

  • Using well known formula, i.e, formula of perimeter of rectangle ::

  • \underline{\boxed{\bf{\red{Perimeter_{(rectangle)} = 2(\ell + b)}}}}

  • Where, \bf{\ell} is length of a rectangle and b is breadth of a rectangle.

\:

\clubsuit Putting all values in formula :

\:

➥ㅤ 2[n + (n + 15)] = 150

\:

➥ㅤ 2(n + n + 15) = 150

\:

➥ㅤ 2(2n + 15) = 150

\:

➥ㅤ 4n + 30 = 150

\:

➥ㅤ 4n = 150 – 30

\:

➥ㅤ 4n = 120

\:

➥ㅤ n = \sf{\cancel{\dfrac{120}{4}}}

\:

After cancelling 120 with 4, we get :

\:

➥ ㅤ\underline{\boxed{\bf{\purple{n = 30}}}}\:\bigstar

\:

Hence,

\:

  • Breadth = n = 30 cm

  • Length = n + 15 = 30 + 15 = 45 cm

\:

⠀⠀⠀━━━━━━━━━━━━━━━━━━━━━━

\:

  • Therefore, dimensions of a rectangle are 30 cm and 45 cm.

\:

\clubsuit Know More :

\:

  • Perimeter of square = 4 × side

  • Perimeter of circle = 2πr

  • Perimeter of equilateral ∆ = 3 × side

\:

━━━━━━━━━━━━━━━━━━━━━━━━━

Answered by sethrollins13
132

Given :

  • The length of a rectangle is 15 cm greater than its breadth.
  • Perimeter of Rectangle is 150 cm.

To Find :

  • Dimensions of the Rectangle .

Solution :

\longmapsto\tt{Let\:Breadth\:be=x}

As Given that length of a rectangle is 15 cm greater than its breadth . So ,

\longmapsto\tt{Length=x+15}

Using Formula :

\longmapsto\tt\boxed{Perimeter\:of\:Rectangle=2(l+b)}

Putting Values :

\longmapsto\tt{150=2(x+15+x)}

\longmapsto\tt{150=2(2x+15)}

\longmapsto\tt{\cancel\dfrac{150}{2}=2x+15}

\longmapsto\tt{75-15=2x}

\longmapsto\tt{60=2x}

\longmapsto\tt{x=\cancel\dfrac{60}{2}}

\longmapsto\tt\bf{x=30}

Value of x is 30 .

Therefore :

\longmapsto\tt{Length\:of\:Rectangle=30+15}

\longmapsto\tt\bf{45\:cm}

\longmapsto\tt{Breadth\:of\:Rectangle=x}

\longmapsto\tt\bf{30\:cm}

Similar questions