The length of a rectangle is 15 m more than its breadth if the perimeter of rectangle is 80m find the dimensions of the rectangle
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let breadth of rectangle be x
then length is (x+15)
perimeter of rectangle=2(l+b)
80=2(x+x+15)
80=4x+30
4x=80-30
=50/4
l=25/2
b=25/2+15
=55/2
dimension=√(25/2)^2+(55/2)^2
√625/4+3025/4
√3650/4
15.10m
then length is (x+15)
perimeter of rectangle=2(l+b)
80=2(x+x+15)
80=4x+30
4x=80-30
=50/4
l=25/2
b=25/2+15
=55/2
dimension=√(25/2)^2+(55/2)^2
√625/4+3025/4
√3650/4
15.10m
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