The length of a rectangle is 15 m more than its breadth. If the perimeter of rectangle is 80m, find the dimension of the rectangle
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let the breadth be X
so length is 15+X
according to condition,
2(l+b) = 80
2(15+X +X ) = 80
2(15+2X)= 80
30+4X= 80
so X= 80-30/4
X = 50/4= 12.5 cm
so breadth = 12.5 cm
length =27.5cm
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so length is 15+X
according to condition,
2(l+b) = 80
2(15+X +X ) = 80
2(15+2X)= 80
30+4X= 80
so X= 80-30/4
X = 50/4= 12.5 cm
so breadth = 12.5 cm
length =27.5cm
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varun2003k:
pls mark as brainliest
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