the length of a rectangle is 16 cm and its perimeter is equal to the perimeter of a square with side 12.5cm find the area of the rectangle
Answers
Answered by
56
perimeter of square=4×side
=4×12.5
=50cm
let the breadth of rectangle be x cm
perimeter of rectangle=2(length+breadth)
50=2(16+x)
50=32+2x
2x=18
x=9
therefore breadth of rectangle=9cm
area of rectangle=length×breadth
=16×9
=144 cm^2
=4×12.5
=50cm
let the breadth of rectangle be x cm
perimeter of rectangle=2(length+breadth)
50=2(16+x)
50=32+2x
2x=18
x=9
therefore breadth of rectangle=9cm
area of rectangle=length×breadth
=16×9
=144 cm^2
Answered by
32
square:
side=12.5 cm
p=4a
=4*12.5
=50cm
p of rectangle = p of square (given)
p of rectangle = 50cm
rectangle:
length = 16cm
p=50cm
p=2(l+b)
=2(16+b)
50=32+2b
18=2b
b=9cm
area=lb
16cm*9cm
=144cm²
side=12.5 cm
p=4a
=4*12.5
=50cm
p of rectangle = p of square (given)
p of rectangle = 50cm
rectangle:
length = 16cm
p=50cm
p=2(l+b)
=2(16+b)
50=32+2b
18=2b
b=9cm
area=lb
16cm*9cm
=144cm²
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