Question

the length of a rectangle is 16 cm and the length of its diagonal is 20 cm . the area of the rectangle is

Answer 1

Answer:

Area of the rectangle will be 192cm²

Step by step explanation:

Assuming breadth as x metres

Using Pythagoras theorem :

⟹ 20² = 16² + x²

⟹ 400 = 256 + x²

⟹ 400 - 256 = x²

⟹ 144 = x²

⟹ x = √144

⟹ x = 12cm

Now,

We know that,

Area of a rectangle = l × b

= 12 × 16

= 192cm² ans.

Answer 2

Given:

Diagonal of a rectangle = 20 cm

Length of the rectangle = 16 cm

Find:

Area of the rectangle

Solution:

The length of the rectangle is 16cm.

The diagonal of the rectangle is 20cm.

Pythagoras theorem

Hypotenuse² = base² + Perpendicular²

Hypotenuse = 20 cm

Base = 'b' cm

Perpendicular = 16 cm

=> (20)² = b² + 16

=> 400 = b² + 256

=> 400 - 256 = b²

=> 144 = b²

=> √144 = b

=> 12 = b

=> b = 12cm.

The base of the rectangle is 12 cm.

We know that,

The area of rectangle = length × breadth

Length = 16 cm

Breadth = 12 cm

=> 16 × 12

=> 192cm²

Hence, the area of rectangle is 192 cm².

I hope it will help you.

Regards.