Question

The length of a rectangle is 16 cm and the length of its diagonal is 20 cm. Find the area of the rectangle​​

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Answer 1

Let ABCD be the rectangular plot.

Then, AB = 16 cm and AC = 20 cm BC =?

According to Pythagoras theorem, From right angle triangle ABC, we have:

= AC²= AB²+ BC²

= 202 = 162 + BC²

=BC²= 202 – 162

= BC²= 400 – 256

= BC² = 144

= BC = √144

= BC = 12 cm

Hence, the area of the rectangle plot = (l × b)

Where, l = 16 cm, b = 12 cm

Then, = (16 × 12) = 192 cm²

Answer 2

Answer:

ANSWER

(c) 192cm

2

Because,

Let ABCD be the rectangular plot.

Then, AB=16cm and AC=20cm

BC=?

According to Pythagoras theorem,

From right angle triangle ABC, we have:

=AC

2

=AB

2

+BC

2

=20

2

=16

2

+BC

2

=BC

2

=20

2

−16

2

=BC

2

=400−256

=BC

2

=144

=BC=

144

=BC=12cm

Hence, the area of the rectangle plot =(l×b)

Where, l=16cm,b=12cm

Then,

=(16×12)

=192cm

2