the length of a rectangle is 16 m less than two times its breath. if the perimeter of rectangle is 112 m, find the length and the breath. solve by method.
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Answered by
3
Let the breadth be x and then length will be 2x-16
Perimeter of rectangle =2(x+2x-16)
112=2(3x-16)
112/2 =3x-16
56=3x-16
56+16=3x
72=3x
72/3=x
24=x
Then the breadth is 24m and lenght is (2*24)-16=48-16 =32
I hope this will help you
Perimeter of rectangle =2(x+2x-16)
112=2(3x-16)
112/2 =3x-16
56=3x-16
56+16=3x
72=3x
72/3=x
24=x
Then the breadth is 24m and lenght is (2*24)-16=48-16 =32
I hope this will help you
Answered by
0
heya friend
your answer goes like this
let ,
breadth of the rectangle to x
then , length of rectangle is 2x - 16
Perimeter of rectangle is 2 ( l + b ) = 112
=> 2 ( 2x - 16 + x ) =112
=> 3x - 16 = 112/2
=> 3x - 16 = 56
=> 3x = 56+16
=> 3x = 72
=> x = 72 / 3
=> x = 24
there fore,
length of rectangle = x = 24m
breadth of rectangle is 2x - 16 = ( 2× 24 - 16 ) = 48 - 16 = 32m
your answer goes like this
let ,
breadth of the rectangle to x
then , length of rectangle is 2x - 16
Perimeter of rectangle is 2 ( l + b ) = 112
=> 2 ( 2x - 16 + x ) =112
=> 3x - 16 = 112/2
=> 3x - 16 = 56
=> 3x = 56+16
=> 3x = 72
=> x = 72 / 3
=> x = 24
there fore,
length of rectangle = x = 24m
breadth of rectangle is 2x - 16 = ( 2× 24 - 16 ) = 48 - 16 = 32m
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