Question

the length of a rectangle is 16cm and it's diagonal is 20cm find the area of the rectangle​

Answer 1

l= length

d= diagonal

A= WL

d =

$\sqrt{w {}^{2} }+\sqrt{l {}^{2} }$

$a = l \sqrt{d ^{2} } - \sqrt{l} {}^{2}$

= 16

$\sqrt{20 {}^{2} } - \sqrt{16 {}^{2} } \\ = 192cm {}^{2}$

hope it helps

pls mark as Brainliest