the length of a rectangle is 16m less than two times its breadth. if the perimeter of the rectangle is 112 m, find the length and the breadth?
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Hi ,
Let the breadth of the rectangle = x m
length = ( 2x - 16 )m
Perimeter ( p ) = 112 m
2 ( length + breadth ) = 112
( 2x - 16 + x ) = 112/2
3x - 16 = 56
3x = 56 + 16
3x = 72
x = 72/3
x = 24
Therefore ,
Breadth = x = 24 m
Length = 2x - 16
= 2 × 24 - 16
= 48 - 16
= 32 m
I hope this helps you.
:)
Let the breadth of the rectangle = x m
length = ( 2x - 16 )m
Perimeter ( p ) = 112 m
2 ( length + breadth ) = 112
( 2x - 16 + x ) = 112/2
3x - 16 = 56
3x = 56 + 16
3x = 72
x = 72/3
x = 24
Therefore ,
Breadth = x = 24 m
Length = 2x - 16
= 2 × 24 - 16
= 48 - 16
= 32 m
I hope this helps you.
:)
leesoulbee:
in the step number 5 from where did the second 2 came from
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