the length of a rectangle is 16m less than two times its breadth. if the perimeter of the rectangle is 112m,find the breadth
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Answered by
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Let the breadth of rectangle be x m
then length = (2x - 16) m
Perimeter = 112m. (given)
We know that,
perimeter of rectangle = 2(l+b)
A/Q,
➡2( x + 2x - 16) = 112
➡ x+ 2x- 16 = 112/2
➡ 3x = (112/2) + 16
➡ 3x = 56 + 16
➡ 3x = 72
➡ x = 24
So breadth = x m = 24 m
& length = (2x -16) = (2*24-16)
➡ 48-16 = 32 m
Hope it will help you !!!
then length = (2x - 16) m
Perimeter = 112m. (given)
We know that,
perimeter of rectangle = 2(l+b)
A/Q,
➡2( x + 2x - 16) = 112
➡ x+ 2x- 16 = 112/2
➡ 3x = (112/2) + 16
➡ 3x = 56 + 16
➡ 3x = 72
➡ x = 24
So breadth = x m = 24 m
& length = (2x -16) = (2*24-16)
➡ 48-16 = 32 m
Hope it will help you !!!
Anonymous:
If it helps you, mark as brainliest !!!
Answered by
2
Breadth of the rectangle is 24m and length is 32m
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