Question

The length of a rectangle is 17/5 m and breadth is 10/3m. Find its area and perimeter. ​

Answer 1

Let the length of the rectangle be 'l' m and breadth be 'b' m

According to question :-

We have to find the area of the rectangle

$\large \bf \red{Area = Length \times Breadth }$

Putting the given values in formula, we get

$\pink{\implies\rm{Area = \frac{17}{\cancel{5}} \times \frac{\cancel{10}}{3}}}$

$\green{⟹ \rm{Area = \cancel\frac{34}{3}}}$

$\implies \large\bf\red{Area = 11.34\: {m}^{2}}$

Thus, the area of rectangle is 11.34 m²

Now, we have to find the Perimeter of rectangle

$\bf{Perimeter = 2(Length + Breadth) }$

$\blue{\implies \rm{Perimeter =2 (\frac{17}{5}+\frac{10}{3})}}$

$\implies \rm{Perimeter = 2(\frac{51+50}{15})}$

$\implies \rm{Perimeter =(\frac{ 2 \times 101}{15})}$

$\implies\rm{Perimeter = \cancel\dfrac{202}{15}}$

$\implies \large\rm\red{Perimeter = 13. 46\: m}$

Thus, the Perimeter of rectangle is 13.46 m

$\large{\boxed {\underline \red{\underline{\bf{FINAL\:ANSWER:-}}}}}$

${\boxed{\boxed{\bf{\red{AREA = 11.34\:{m}^{2}}}}}}$

${\boxed{\boxed{\bf{\red{PERIMETER = 13.46\: m}}}}}$

Answer 2

Step-by-step explanation:

area of rectangle = l*b

= 17/5 *10/3

= 11.33

perimeter of rectangle= 2(l+b)

= 2(17/5+10/3)

= 51+50/15

= 101/15= 6.73