Question

the length of a rectangle is 17/5m and it's breadth is 10/3m. find its area and perimeter​

Answer 1

Step-by-step explanation:

$17 \div 5 + 10 \div 3 \times 4 = 26.9333$

it is perimeter

$17 \div 5 \times 10 \div 3 = 170 \div 15 = 11.33333$

it is area

Answer 2

$\huge{\boxed{\underline{\underline{\bf{GIVEN:-}}}}}$

• Length of the rectangle = $\bf{\frac{17}{5}\:m}$
• Breadth of the rectangle = $\bf{\frac{10}{3}\:m}$

$\huge{\boxed{\underline{\underline{\bf{TO\:FIND:-}}}}}$

Find the area and perimeter of rectangle = ?

$\huge{\boxed{\underline{\underline{\bf{FORMULA\:USED:-}}}}}$

$\large{\boxed{\bf{\red{Area\: of\:rectangle = L \times B}}}}$

$\large{\boxed{\bf{\red{Perimeter \:of\:rectangle = 2(l+b)}}}}$

$\huge{\boxed{\underline{\underline{\bf{SOLUTION:-}}}}}$

Let the length of the rectangle be 'l' m and breadth be 'b' m

According to question :-

We have to find the area of the rectangle

$\large\bf{Area = Length \times Breadth }$

Putting the given values in formula, we get

$\implies$$\rm{Area = \frac{17}{\cancel{5}} \times \frac{\cancel{10}}{3}}$

$\implies$$\rm{Area = \cancel\frac{34}{3}}$

$\implies$$\large\bf\red{Area = 11.34\: {m}^{2}}$

Thus, the area of rectangle is 11.34 m²

Now, we have to find the Perimeter of rectangle

$\large\bf{Perimeter = 2(Length + Breadth }$

$\implies$$\rm{Perimeter =2 (\frac{17}{5}+\frac{10}{3})}$

$\implies$$\rm{Perimeter = 2(\frac{51+50}{15})}$

$\implies$$\rm{Perimeter =(\frac{ 2 \times 101}{15})}$

$\implies$$\rm{Perimeter = \cancel\dfrac{202}{15}}$

$\implies$$\large\rm\red{Perimeter = 13. 46\: m}$

Thus, the Perimeter of rectangle is 13.46 m

$\large{\boxed{\underline{\underline{\bf{FINAL\:ANSWER:-}}}}}$

$\huge{\boxed{\boxed{\bf{\red{AREA = 11.34\:{m}^{2}}}}}}$

$\huge{\boxed{\boxed{\bf{\red{PERIMETER = 13.46\: m}}}}}$