The length of a rectangle is 2 cm longer than it's width. If the area of the rectangle is 48 cm². Find it's perimeter.
Answers
⚘ Question :-
The length of a rectangle is 2 cm longer than it's width. If the area of the rectangle is 48 cm². Find it's perimeter.
⚘ Answer :-
Perimeter of rectangle is 28 cm.
Explanation:
⚘ Given :-
Length = Width + 2 cm
Area of rectangle = 48 cm²
⚘ To Find :-
Perimeter of rectangle = ?
⚘ Solution :-
Let width of rectangle be m cm.
As it is stated in question that the length of a rectangle is 2 cm longer than it's width. So, length of rectangle is (m + 2) cm.
★ F I N D I N GㅤV A L U EㅤO Fㅤ'm'ㅤ::
We know that,
Where,
L denotes length of rectangle
W denotes width of rectangle
We have,
L = (m + 2) cm
W = m cm
= 48 cm²
According to the question by using the formula we get,
➨
➨
➨
➨
By splitting the middle term we get,
➨
➨
➨
➨
➨
➨
➨
Width can't be negative
∴ Width of rectangle is 6 cm.
Now,
➠ Length of rectangle = (m + 2) cm
Put m = 6 in above equation we get,
➠ Length of rectangle = (6 + 2) cm
➠ Length of rectangle = 8 cm
∴ Length of rectangle is 8 cm.
★ F I N D I N GㅤP E R I M E T E Rㅤ::
We know that,
Where,
L denotes length of rectangle
W denotes width of rectangle
We have,
L = 8 cm
W = 6 cm
According to the question by using the formula we get,
➨
➨
➨
➨
∴ Perimeter of rectangle is 28 cm.
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