Question

The length of a rectangle is 2 cm more than its width. If it's perimeter of the rectangle is 48 cm . Find its area in cm ²​

Answer 1

Answer:

• Area of Rectangle = 143 cm²

Step-by-step explanation:

Given:

• Length of Rectangle is 2 cm more that it's width.
• Perimeter of Rectangle = 48 cm

To Find:

• Area of Rectangle.

According to question,

Let, width of Rectangle be 'x' cm.

And, Length of Rectangle be '(x + 2)' cm.

Now, we know that,

=> Perimeter of Rectangle = 2(l + b)

=> 48 = 2(2 + x + x)

=> 48 = 2(2 + 2x)

=> 48 = 4 + 4x

=> 4x = 44

=> x = 44/4

=> x = 11 cm.

So, Width of Rectangle = 11cm

And, Length of Rectangle = 11 + 2 = 13 cm.

Now, we will calculate area of Rectangle,

=> Area of Rectangle = length × width

=> Area of Rectangle = 13 × 11

=> Area of Rectangle = 143 cm²

Hence, Area of Rectangle = 143 cm².

Answer 2

Answer :

$\rule{100}2$

Given :

In a rectangle,

• Length = 2 cm + width
• Perimeter = 48

To Find :

• Area of the given rectangle

Solution :

Let width of the rectangle be ' x '

So, it's length will be ' x + 2 '

We know that,

$\sf Perimeter\:of\:Rectangle=2(length+breadth)$

$\sf 48 = 2 ( x + x + 2 )$

$\sf\implies 48 = 2 ( 2x + 2 )$

$\sf\implies 48 = 4x + 4$

$\sf\implies 48 - 4 = 4x$

$\sf\implies 44 = 4x$

$\sf\implies x =\dfrac{44}{4}$

$\sf\therefore x = 11$

Hence,

width of the rectangle = 11 cm.

Length => 2 + 11 = 13

Now,

$\sf Area\: of\: Rectangle = length\times breadth$

Substitute the given values. we get,

= 11 × 13

= 143 cm²

Therefore, Area of the given rectangle is 143 cm²

$\rule{200}2$