the length of a rectangle is 2 cm more than the width.If the area of the rectangle is 120 square cm,what is the perimeter of the rectangle?
Answers
Answered by
0
Step-by-step explanation:
Given:
Area of rectangle=120 sq. cm
Now let width be x cm,
so length =x+2cm
to find perimeter we need width so,
Area of rectangle =lxb
i.e 120 =(x) x (x+2)
120=2x+2; 120-2/2=x; 90= x
:. width is 90 and lenth is 92
now perimeter of rectangle= 2(l+b)=2(92 + 90)=2x182= 364 cm
:. perimeter of the rectangle is 364 cm.
Answered by
1
Answer:
Step-by-step explanation:
l = b+2
Area = 120 cm = l*b
Area = l*b
120 = b+2*b
120 = b^2 +2b
b^2 +2b - 120 = 0
b^2 +12b - 10b -120 = 0.
b(b+12) - 10(b+12) = 0.
(b+12)(b-10) = 0.
b= -12 or b =10.
As breadth cant be negative.
b = 10.
l*b = 120
l * 10 =120.
l = 12 cm.
Perimeter = 2(l+b).
2(12+10) = 2(22) = 44 cm.
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