Question

the length of a rectangle is 2 cm more than twice its breadth and it's perimeter is 40 cm find the area of the rectangle​

Answer 1

Answer:

Area of the rectangle is 64cm²

Explanation :

We know that,

Area of a rectangle = l × b

In the given rectangle,

Lenght is two more than twice its breadth.

Or,

→ l = 2b + 2

Note :

• ‘l’ and ‘b’ is the lenght and breadth respectively.

We know that,

Perimeter of a rectangle = 2(l + b)

But, it's perimeter is 40cm. (given)

According to the question :

→ 40 = 2[(2b + 2) + b]

→ 40 = 2(3b + 2)

→ 40/2 = 3b + 2

→ 20 = 3b + 2

→ 20 - 2 = 3b

→ 18 = 3b

→ 18/3 = b

→ 6 = b

Therefore, the breadth of the rectangle is 6cm.

So, the length will be : 2b + 2

= 2(6) + 2

= 12 + 2

= 14cm.

Area of the rectangle = 14 × 6

= 64cm²

Required answer : 64cm²

Answer 2

Step-by-step explanation:

given length 2cm

perimeter 40cm

Let breadth be x

length of the pool is (2x+2)

so first find breadth using perimeter

• 2(length +breadth) =40
• 2[(2x+2)+x]=40
• 2(3x+2)=40
• 3x+5=40÷2
• 3x+5=20
• 3x=20-5
• 3x=15
• x=15÷3
• x=5

breadth is 5

length is 2

so area=l×b

=2×5

=10

area is 10 cm