Question

The length of a rectangle is 2 feet more than it's width. How do you find the dimensions of the rectangle if its area is 63 square feet?

Answer 1

Let the width be x ft

Then length is 2+x ft

Area =length * width

63=x(2+x)

63=x_2 +2x

x_2+2x-63=0

x_2+9x-7x-63=0

x(x+9)-7(x+9)=0

(x+9) ( x-7)=0

x+9=0 or x-7=0

x=-9, but x cannot be negative

Hence x=7

Length is x+2; 7+2=9 ft

Width is 7 ft

Answer 2

Area of rectangle = l×b= 63 square feet

let width be x

then length is x+2

Now, Area = x × (x+2) = 63