Question

The length of a rectangle is 2 less than twice the width. If the perimeter is 11m, find the length and width.

Answer 1

Answer:

Let x and y be the length and breadth of the rectangle. Then the perimeter is 2x+2y.

We have the first equation 2x+2y = 3x-11 which is same as x-2y = 11………….(1).

The second equation is (1/7)(2x+2y) = b+(2/27)x which reduces to 8x-27y= 0……..(2)

Solving (1) and (2) we get x= 27 and y= 8.

Hence the perimeter = 2x+2y which is equal to 70 m and the breadth is y which is 8 metres.

Step-by-step explanation:

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