Question

The length of a rectangle is 2 m more than its breadth. Find the dimensions of the rectangle if its perimeter is 56 m.​

Answer 1

Answer:

let the breadth of triangle be x and also length be x+2

(x+x+2)×2 = 56

(2x+2)×2 =56

4x+4 = 56

4x = 52

x = 13

breadth = x = 13

height= x+2 = 13+2= 15

Answer 2

Let the the breadth of rectangle be x m and length be x + 2 m .

♧Parameter of rectangle = 56m

● Parameter of rectangle = 2(length +breadth)

♤ 56 = 2(x+2+x)

♤ 28 = 2x+2

♤ 26 = 2x

♤ x = 13

Hence,

Length = x+2 = 15m

Breadth = x = 13m