Question

The length of a rectangle is 2 more than 3 times the width. If the perimeter is 100, find the length and width of the rectangle.

If l = length and w = width, which of the following systems could be used to solve the problem?

l = 3w + 2 and 2l + 2w = 100
l = 2w + 3 and 2l + 2w = 100
l + 2 = 3w and 2l + 2w = 100

Answer 1

Answer:

l=3w+2

2l+2w=100

on solving we get

l=38

w=12

Answer 2

Answer:

l = 2w + 3 and 2l + 2w = 100

You can use elimination method for solving the problem