Question

The length of a rectangle is 2 more than thrice its width. Find its dimensions if its perimeter is 76 units.

Answer 1

Given

Length of a Rectangle is 2 more than thrice it's width. Perimeter is 76 units.

To Find

We have to find its dimensions

$\sf\huge {\underline{\underline{{Solution}}}}$

Since,we don't know it's dimensions so,let us assume some Variable.

Let the Breadth of the Rectangle be 'x'

Then length is 2 more than thrice its width

Thrice of width = 3*x= 3x

According to the question:

length of the Rectangle= 2+3x

Perimeter of the Rectangle= 2(l+b)

Where l is the length and b is the breadth

Perimeter of Rectangle= 2(2+3x+x)

=> 76= 2(4x+2)

=> 76= 8x+4

=> 76-4=8x

=> 72= 8x

=> x= 9

x=9

Therefore, breadth is 9 units

Length = 2+3x=> 2+3(9)= 29

Length is 29 units

Check:

Perimeter of Rectangle= 2(9+29)

Perimeter of Rectangle= 2(38)= 76 units

More information=>

Perimeter is the total distance occupy by a solid 2D figure around its edge.

Area of Rectangle= length *breadth