Question

The length of a rectangle is 2 unit more than its breadth. If it's area is 80 square unit. Calculate it's sides?

Answer 1

Answer:

Length=10

Breadth =8

Step-by-step explanation:

Let length of the rectangle be x+2 units

Then breadth of the rectangle will be x units

Area=length×breadth

Area=(x+2)(x)

80=x^2+2x

X^2+2x-80=0

X^2+10x-8x-80

X(x+10)-8(x+10)

(x+10)(x-8)

X=-10 or 8

It can't be negative, so x=8

X+2=10

Length =10,breadth =8

Answer 2

Answer:

$\boxed{\red{\bf Length = 10 \: units.}}$

$\boxed{\red{\bf Breadth = 8 \: units.}}$

Step-by-step explanation:

Given that :

• The length of a rectangle is 2 unit more than its breadth.
• Area of rectangle is 80 sq. unit.

To find :

• The length and breadth of the rectangle.

Solution :

Let the breadth of the rectangle be x unit. Then, it breadth would be (x + 2) units.

According to the question ;

Area of rectangle = 80 sq unit.

⇒ Length * Breadth = 80 sq unit.

⇒ x ( x + 2 ) = 80

⇒ x² + 2x = 80

⇒ x² + 2x - 80 = 0

⇒ x² + 10x - 8x - 80 = 0

⇒ x (x + 10) - 8(x + 10) = 0

⇒ (x - 8)(x + 10) = 0

⇒ x = 8 or x = - 10

Since, the length can't be negative.

The value of x is 8.

• Length = (x + 2) = 10 units.
• Breadth = x = 8 units.

Hence, the length and breadth of the rectangle are 10 units and 8 units respectively.