the length of a rectangle is 2 x + 3 units and the corresponding breadth is 2 x minus 3 units find the area of the rectangle in terms of X what will be the area of rectangle if x is equal to 30 units
Answers
Answer:
Length , l = 2x +3 units
Breadth, b = 2x - 3 units
Area of rectangle= l×b
Area of rectangle = (2x+3)(2x-3)
[ using identity (a+b)(a-b)= a^2-b^2 ]
Area of rectangle= (2x)^2 - (3)^2
Area of rectangle =4x^2 - 9
So, area of rectangle in terms of x will be 4x^2 -9 square units.
When x =30 units
Then,
Area of rectangle= 4(30)^2 -9
Area of rectangle= 4×900 -9
Area of rectangle = 3591 sq. units
Given :-
- Length of the rectangle (l) = (2x + 3) units
- Breadth of the rectangle (b) = (2x - 3) units
To Find :-
- Area of the rectangle in terms of x = ?
- Area of the rectangle if x is 30 units = ?
Concept Used :-
- (a + b)² = a² + b² + 2ab
- (a - b)² = a² + b² - 2ab
- (a + b) (a - b) = a² - b²
- Area of rectangle = Length × Breadth
Solution :-
Let's find the area of the rectangle.
❖ Area of rectangle = Length × Breadth
⇒ Area of rectangle = (2x + 3) × (2x - 3) unit²
⇒ Area of rectangle = (2x)² - (3)² unit² [Using (a + b) (a - b) = a² - b²]
⇒ Area of rectangle = (4x² - 9) unit²
∴ The area of rectangle in terms of x is (4x² - 9) unit².
Now we put the value of x as 30
◆ Area of rectangle = (4x² - 9) unit²
⇒ Area of rectangle = [{4 × (30)²} - 9] unit²
⇒ Area of rectangle = {(4 × 900) - 9} unit²
⇒ Area of rectangle = (3600 - 9) unit²
⇒ Area of rectangle = 3,591 unit²
∴ The area of rectangle when x is 30 units is 3591 unit².
Additional Information :-
- Perimeter of rectangle = 2(Length + Breadth)
- Area of rectangle = Length × Breadth
- Length of diagonal of rectangle = √Length² + Breadth²
- Perimeter of square = 4 × Length of a side of square
- Area of square = Side²
- Length of diagonal of square = Side√2
- Perimeter of triangle = Length of the sides of triangle
- Area of triangle = ½ × Base × Height