The length of a rectangle is 2 yards less than 3 times the width. The perimeter is 68 yards. Find the length and the width.
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Answered by
12
Question:-
The length of a rectangle is 2 yards less than 3 times the width. The perimeter is 68 yards. Find the length and the width.9
Answer:-
- The sides of rectangle are 25 yards and 9 yards.
Solution:-
- Length = 3x - 2 yards
- Breadth = x yards
- Perimeter = 68 yards
- The value of x is 9 yards.
_________________________
- Length = 3x - 2 = 3(9) - 2 = 25 yards
- Breadth = x = 9 yards
_________________________
The sides of rectangle are 25 yards and 9 yards.
Answered by
16
Answer :-
- Dimensions of the rectangle are 9 yards and 25 yards respectively.
Given :-
- The length of a rectangle is 2 yards less than 3 times the width. The perimeter is 68 yards.
To Find :-
- Length and width of the rectangle.
Solution :-
Let
- Breadth of the rectangle be x
- Length of the rectangle will be 3x - 2
Given
- The perimeter of the rectangle is 68yards.
As we know that
- Perimeter of the rectangle is 2 (l + b)
Where
- l = length
- b = breadth
According to question :-
⇒ 2 {(3x - 2) + x} = 68
⇒ 2 { 3x - 2 + x } = 68
⇒ 2 { 3x + x - 2 } = 68
⇒ 2 { 4x - 2 } = 68
⇒ 4x - 2 = 68/2
⇒ 4x - 2 = 34
⇒ 4x = 34 + 2
⇒ 4x = 36
⇒ x = 36/4
⇒ x = 9
Now
- Breadth of the rectangle = x = 9 yards
- Length of the rectangle = 3x - 2 = 3(9) - 2 = 25 yards
Hence, the dimensions of the rectangle are 9 yards and 25 yards respectively.
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