the length of a rectangle is 20 and its diagnol ia 34.Find it's breadth and perimeter
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as we know that a rectangle has 90 at its corner ,
then, by pythagoras theorem,
(34)^2 = (20)^2 + (breadth)^2
1156 = 400+ (breadth)^2
1156-400 = (breadth)^2
756= (breadth)^2
root 756 = breadth
27.4954541... = breadth
which can be written as 27.5
then ,
breadth= 27.5
area of rectangle = length*breadth
here, area of rectangle =27.5 *20
area of rectangle = 550
perimeter of rectangle = 2(l+b)
perimeter = 2(27.5+20)
perimeter = 2*47.5
perimeter = 95
i hope this will help
- by ABHAY
then, by pythagoras theorem,
(34)^2 = (20)^2 + (breadth)^2
1156 = 400+ (breadth)^2
1156-400 = (breadth)^2
756= (breadth)^2
root 756 = breadth
27.4954541... = breadth
which can be written as 27.5
then ,
breadth= 27.5
area of rectangle = length*breadth
here, area of rectangle =27.5 *20
area of rectangle = 550
perimeter of rectangle = 2(l+b)
perimeter = 2(27.5+20)
perimeter = 2*47.5
perimeter = 95
i hope this will help
- by ABHAY
rumpachandra:
yeah
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I hope it helps you.....
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If there is any queries please tell me.....
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