The length of a rectangle is 20 cm more than its breadth if the perimeter is 100 cm . find the dimension of the rectangle .
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• Given
- Length of the rectangle is 20 cm more than the breadth.
- Perimeter of the rectangle = 100 cm
• To find
- Dimensions of the rectangle
• Solution
Let the breadth be x cm and length be (x + 20) cm.
Perimeter of the rectangle = 100 cm
• Perimeter of rectangle = 2(l + b)
⟶ 100 = 2(x + x + 20)
⟶ 100 = 2(2x + 20)
⟶ 100 = 4x + 40
⟶ 100 - 40 = 4x
⟶ 60 = 4x
⟶ 60/4 = x
⟶ 15 = x
The value of x = 15
- Dimensions of the rectangle -
- Length of the rectangle = (x + 20) = 15 + 20 = 35 cm
- Breadth of the rectangle = x = 15 cm
______________________________________
Let's verify -
Perimeter of the rectangle = 100 cm
Length of the rectangle = 35 cm
Breadth of the rectangle = 15 cm
• Perimeter of rectangle = 2(l + b)
⟶ 2(35 + 15)
⟶ 2(50)
⟶ 100
Hence, verified.
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