the length of a rectangle is 20 CM more than its breadth. if the perimeter is 100 cm find the dimension of the rectangle.
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14
Let the breath of the rect. be b,
then length of text. = b + 20
3(b+b+20)=100
4b+40=100
4b=100-40
4b=60
b=60/4
b=15
length = 15&20. (that is b+20)
= 35m
hence L=35, b =15 cm
then length of text. = b + 20
3(b+b+20)=100
4b+40=100
4b=100-40
4b=60
b=60/4
b=15
length = 15&20. (that is b+20)
= 35m
hence L=35, b =15 cm
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