Question

The length of a rectangle is 20cm more than its breadth if the perimeter is 100 find the dimension of the rectangle

Answer 1

Hello Dears
Here is the solution
soln:-
Let the breadth be x
so length =x+20
A/q,
2(l+b)=100
2(x+20+x)=100
2(2x+20)=100
4x+40=100
4x=100-40
x=60/4
=15
so breadth =15cm
length =15+20=35cm
Hope it helps

Answer 2

⠀

$\huge{\underline{\underline{\sf{\blue{SOLUTION:-}}}}}$

⠀

$\sf{\underline{\green{AnswEr:-}}}$

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

• Breadth of rectangle = 15 Cm
• Length of rectangle = 35 Cm

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

$\sf{\underline{\green{Given:-}}}$

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

• The length of a rectangle is 20cm more than its breadth. If the perimeter is 100.

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

$\sf{\underline{\green{Find:-}}}$

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

• Breath of rectangle = ?
• Length of rectangle = ?

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

$\sf{\underline{\green{Explanation:-}}}$

Let the other number be y.

$\:\:\:\:\dag\bf{\underline{\underline \red{Then:-}}}$

• Length = y + 20 Cm

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

$\:\:\:\:\dag\bf{\underline{\underline \red{Now:-}}}$

$\sf\underline{\purple{\:\:\: Perimeter = 2 \times (Length + Breadth)\:\:\:}}$

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

$\sf{Perimeter = 2 \times (y + y + 20)}$

$\sf{Perimeter = 2 \times (2y + 20)}$

$\sf{Perimeter = 4y + 40}$

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

$\sf{\underline\pink{A.T.Q:-}}$

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

$\longrightarrow \sf {4y + 40 = 100}$

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

$\longrightarrow \sf {4y = 100 - 40}$

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

$\longrightarrow \sf {4y = 60}$

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

$\longrightarrow \sf {y = \cancel\dfrac{60}{4} }$

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

$\longrightarrow \sf {y = 15}$

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

$\:\:\:\:\dag\bf{\underline{\underline \red{Hence:-}}}$

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

• Breath of rectangle = 15 Cm

• Length of rectangle = 15 + 20

• Length of rectangle = 35 Cm

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

$\rule{200}{2}$