Question

The length of a rectangle is 24cm and the width is 10cm. How long is the diagonal???
Please help me.. answer with an explanation​

Answer 1

$\purple{\bigstar}$ Length of the Diagonal is$\large\leadsto\boxed{\tt\red{26 \: cm}}$

• Given:-

• Length of a rectangle is 24 cm

• Width of a rectangle is 10 cm

• To Find:-

• Length of the diagonal

★ Figure:-

$\setlength{\unitlength}{1cm}\begin{picture}(0,0)\thicklines\multiput(0,0)(5,0){2}{\line(0,1){3}}\multiput(0,0)(0,3){2}{\line(1,0){5}}\put(2,-0.7){\sf\large 24 cm}\put(-1.5,1.5){\sf\large 10 cm}\put(-0.5,-0.4){\bf A}\put(-0.5,3.2){\bf D}\put(5.3,-0.4){\bf B}\put(5.3,3.2){\bf C}\qbezier(0,0)(0,0)(5,3)\put(2.20,1.7){\sf\huge d}\end{picture}$

• Solution:-

We know, Diagonal of a rectangle:-

$\pink{\bigstar}$ $\underline{\boxed{\bf\green{Diagonal = \sqrt{(length)^2 + (width)^2}}}}$

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

• Substituting in the values:-

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

➪ $\sf Diagonal = \sqrt{(24)^2 + (10)^2}$

➪ $\sf Diagonal = \sqrt{576 + 100}$

➪ $\sf Diagonal = \sqrt{676}$

★ $\large{\bf\pink{26 \: cm}}$

Therefore, the length of the Diagonal is 26 cm.