The length of a rectangle is 24cm.The length of its diagonal is 30cm.Find the area of the rectangle.
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Answered by
87
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Let ABCD is a rectangle.
Length of rectangle = AB = CD = 24 cm
Breadth of rectangle = AD = BC = ?
Let Diagonal (AC ) = 30 cm
By Pythagoras theorem , we have :
BC = ✓ ( AC)² - (AB)² = ✓(30)² - (24)²
=> ✓( 30 + 24 ) ( 30-24)
=> ✓54 × 6
=> ✓324
=> 18 cm
Breadth ( AD ) = BC = 18 cm
Therefore,
Area of rectangle = L × B
=> 24 × 18
=> 432 cm².
Let ABCD is a rectangle.
Length of rectangle = AB = CD = 24 cm
Breadth of rectangle = AD = BC = ?
Let Diagonal (AC ) = 30 cm
By Pythagoras theorem , we have :
BC = ✓ ( AC)² - (AB)² = ✓(30)² - (24)²
=> ✓( 30 + 24 ) ( 30-24)
=> ✓54 × 6
=> ✓324
=> 18 cm
Breadth ( AD ) = BC = 18 cm
Therefore,
Area of rectangle = L × B
=> 24 × 18
=> 432 cm².
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Answered by
85
The Diagonal of the rectangle are divides its 2 right angled triangle , so we can use the Pythagorean theorem to solve this problem.
__________-
GIVEN
Length of Rectangle = 24 cm
Diagonal of Rectangle = 30 cm
__________
=> [hyp]² = [lenght]² + [breadth]²
=> 30² = 24² + [breadth]²
=> [breadth]² = 900 - 576 = 324
=> Breadth = 18 cm
___________
NOW,
Area of Rectangle = Length × Breadth
= 24 × 18 = 432 cm²
_________________[ANSWER]
======================================
_-_-_-_☆☆_-_-_-_
__________-
GIVEN
Length of Rectangle = 24 cm
Diagonal of Rectangle = 30 cm
__________
=> [hyp]² = [lenght]² + [breadth]²
=> 30² = 24² + [breadth]²
=> [breadth]² = 900 - 576 = 324
=> Breadth = 18 cm
___________
NOW,
Area of Rectangle = Length × Breadth
= 24 × 18 = 432 cm²
_________________[ANSWER]
======================================
_-_-_-_☆☆_-_-_-_
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